Re: Kendal at Home

From
Will Reid <wreid@thekey.com>
To
Steve Koyanagi <skoyanagi@thekey.com>
CC
Legal <legal@thekey.com>, Timothy Thomas <tt@thekey.com>, Steve Sudberry <ssudberry@thekey.com>, Ashley Mirone <amirone@thekey.com>
Date
Wed, 19 Feb 2025 19:16:38 -0500
Folder
INBOX
--00000000000052e4a6062e87cae2 Content-Type: text/plain; charset="UTF-8" Content-Transfer-Encoding: quoted-printable Thanks Steve, If we=E2=80=99re not submitting a redline copy how do I proceed? Will Reid Partner wreid@thekey.com 513-707-2304 TheKey.com [image: TheKey] On Wed, Feb 19, 2025 at 5:23=E2=80=AFPM Steve Koyanagi wrote: > Agreement looks good/standard. Only pushback on this is our position is a > BAA is not needed given we're excluded from the BAA requirements: > > "The HIPAA Privacy Rule explicitly excludes from the business associate > requirements disclosures by a covered entity to a health care provider fo= r > treatment purposes. See 45 CFR 164.502(e)(1)." > > > https://www.hhs.gov/hipaa/for-professionals/faq/business-associates/index= .html > > Otherwise, good to move forward. Let me know if there are any questions o= r > Kendal wants to discuss. Thanks. > > On Tue, Feb 18, 2025 at 9:26=E2=80=AFAM Will Reid wrot= e: > >> Steve, >> I signed the agreement below in 2020 when Kendal first opened an office >> in Cincinnati. Their model is such that it takes years before their clie= nts >> need our services. As their client count increases I wanted to have you >> review the agreement(s) below. >> >> Thanks, >> >> Will Reid >> Partner >> >> wreid@thekey.com >> 513-707-2304 >> TheKey.com >> [image: TheKey] >> > --00000000000052e4a6062e87cae2 Content-Type: text/html; charset="UTF-8" Content-Transfer-Encoding: quoted-printable Thanks Steve, If we=E2=80=99r= e not submitting a redline copy how do I proceed? Will= Reid Partner wreid@thekey.com 513-707-2304 TheKey.com = On Wed, Feb 19, 2025 at 5:23=E2=80=AF= PM Steve Koyanagi &lt; skoyanagi@thekey.com &gt; wrote: Agreement=C2=A0look= s good/standard. Only pushback on this is our position=C2=A0is a BAA is

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